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class Solution { public String solution(String phone_number) { String answer = ""; return answer; } } 우선 숫자로 들어온 번호를 split를 통해 하나하나 짤라준다 class Solution { public String solution(String phone_number) { String answer = ""; String[] numberArr = phone_number.split(""); for(int i=0; i

class Solution { public long[] solution(int x, int n) { long[] answer = {}; return answer; } } class Solution { public long[] solution(int x, int n) { long[] answer = new long[n]; long temp = x; for(int i=0; i

import java.util.Scanner; class Solution { public static void main(String[] args) { Scanner sc = new Scanner(System.in); int a = sc.nextInt(); int b = sc.nextInt(); System.out.println(a + b); } } import java.util.Scanner; class Solution { public static void main(String[] args) { Scanner sc = new Scanner(System.in); int a = sc.nextInt(); int b = sc.nextInt(); for(int i=0; i

ㅎㅎ..어제 백준풀다 이거 풀어서인지 자꾸 입력까지 코딩해서 에러났다.. class Solution { public String solution(int num) { String answer = ""; return answer; } } class Solution { public String solution(int num) { String answer = ""; if(num%2==0){ answer = "Even"; }else{ answer = "Odd"; } return answer; } } 삼항연산자! public class EvenOrOdd { String evenOrOdd(int num) { return num % 2 == 0 ? "Even": "Odd"; } public static void mai..

일단 첫문제는 내가 풀 수 있을거 같은걸루.. class Solution { public double solution(int[] arr) { double answer = 0; return answer; } } class Solution { public double solution(int[] arr) { double answer = 0; for(int i=0; i